Ncert Exercises & Solutions

Identify the products A and B formed in the following reaction

$C H_{3} — C H_{2} C H = C H — C H_{3} + H C l \to C H_{2} — C H_{2} — C H — C H_{3}$
$|$
$C l$
$(2 - c h l o r o p e n \tan e)$
$+ C H_{3} — C H_{2} — C H — C H_{2} — C H_{3}$
$|$
$(3 - C h l o r o p e n \tan e)$

The carbocation formed from compound (A) is slightly less stable than carbocation

jeading to the formation of compound (B) therefore the amount of 2-chloropentane (B) will

be little bit more than that of 3- chloropentane (A).