A solution of Ni(NO3)2 is electrolysed between platinum electrodes using 0.1 Faraday electricity. The number of moles of Ni that will be deposited at the cathode are:

1. 0.10 2. 0.05
3. 0.20 4. 0.15
Subtopic:  Faraday’s Law of Electrolysis |
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Aluminium oxide may be electrolysed at 1000 °C to furnish aluminium metal.
The cathode reaction is  Al3+ + 3e- → Al.
To prepare 5.12 kg of aluminium metal by this method would require:
(Atomic mass = 27 amu; 1 faraday=96,500 Coulombs)

1. 5.49×101 C of electricity
2. 5.49×104 C of electricity
3. 1.83×107 C of electricity
4. 5.49×107 C of electricity

Subtopic:  Faraday’s Law of Electrolysis |
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How many moles of electrons are required to reduce 1 mole of permanganate ions into manganese dioxide?

1. 3
2. 6
3. 4
4. 7
Subtopic:  Faraday’s Law of Electrolysis |
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If one coulomb of electric charge is passed through a solution of silver nitrate (\(\mathrm{AgNO}_3\)) during electrolysis, what is the mass of silver (in milligrams) deposited at the electrode?
(Molar mass of Ag = 108 g/mol)
1. 1.12 mg  2. 3.26 mg
3. 2.54 mg 4. 4.02 mg
Subtopic:  Faraday’s Law of Electrolysis |
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Electrolysis of Fe₂(SO₄)₃ solution is carried out for 'x' minutes with a current of 1.5 A, depositing 0.3482 g of Fe. What is the value of x to the nearest integer?
[Given: \(1 ~\text{F}=96500 ~\text{C} ~\text{mol}^{-1}\)
Atomic mass of \(\text{Fe}=56~ \text{g}~ \text{mol}^{-1}\)]
1. 20
2. 25
3. 18
4. 17
Subtopic:  Faraday’s Law of Electrolysis |
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