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  • 1(current)
Q. No.

An AC source given by \(V=V_m\sin(\omega t)\) is connected to a pure inductor \(L\) in a circuit and \(I_m\) is the peak value of the AC current. The instantaneous power supplied to the inductor is:

1. \(\dfrac{V_mI_m}{2}\mathrm{sin}(2\omega t)\) 2. \(-\dfrac{V_mI_m}{2}\mathrm{sin}(2\omega t)\)
3. \({V_mI_m}\mathrm{sin}^{2}(\omega t)\) 4. \(-{V_mI_m}\mathrm{sin}^{2}(\omega t)\)
Subtopic:  Power factor |
Level 3: 35%-60%
NEET - 2022
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  • 1(current)
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