A \(2\) kg brick begins to slide over a surface which is inclined at an angle of \(45°\) with respect to horizontal axis. The co-efficient of static friction between their surfaces is –
1.  \(1\)
2. \(0.5\)
3. \(1.7\)
4. \(\frac{1}{\sqrt{3}}\)
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What is the maximum acceleration of a train that allows a box resting on its floor to remain stationary? (given that the coefficient of static friction between the box and the train's floor is \(0.2,\) and the acceleration due to gravity is \(10\) ms-2)
1. zero
2. \(1.0\) ms-2
3. \(2.0\) ms-2
4. \(4.0\) ms-2
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The rope and pulley are ideal and there is no friction anywhere except between the \(10~\text{kg}\)-block and the horizontal plane, where \(\mu\) (coefficient of friction)\(=0.2.\) Take \(g=10~\text{m/s}^2,\) if required.
           
What is the maximum mass \(m\) (shown) that can be suspended from the string so that the system does not move?
1. \(m=10~\text{kg}\)    2. \(m=2~\text{kg}\)   
3. \(m=12~\text{kg}\) 4. \(m=8~\text{kg}\)
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A \(2~\text{kg}\) box is resting on a horizontal floor. A horizontal force of \(30~\text{N}\) is applied to the box, but it does not move. The coefficient of static friction is: (take \(g=10~\text{m/s}^2\))
1. \(\dfrac{2}{3}\) 2. \(\dfrac{3}{2}\)
3. \(\dfrac{1}{2}\) 4. \(\dfrac{1}{3}\)
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A box rests on the floor of a train. The coefficient of static friction between the box and the floor is \(0.25.\) What is the maximum acceleration the train can have without causing the box to slip? \((\text{take}~g= 10 ~\text{ms}^{-2})\)
1. \(10 ~\text{ms}^{-2}\) 2. \(0.25 ~\text{ms}^{-2}\)
3. \(2.5 ~\text{ms}^{-2}\) 4. \(25 ~\text{ms}^{-2}\)
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A light, rigid block is placed on a horizontal surface. A horizontal force \(F_2\) and a vertical force \(F_1\) are exerted on the block, so that it just stops moving due to friction. It is observed that \(F_1=4F_2.\) The coefficient of friction between the block and the surface is:
1. \(1\) 2. \(\dfrac12\)
3. \(\dfrac14\) 4. \(2\)
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A body of mass m is kept on a rough horizontal surface (coefficient of friction= μ). A horizontal force is applied to the body but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by F, where:

1. |F|=mg+μmg

2. |F|=μmg

3. |F|mg1+μ2

4. |F|=mg

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A block moving with speed 1 m/s comes to rest after moving for 20 cm over a rough surface. The coefficient of friction between the block and surface is:
1. 0.25
2. 0.33
3. 0.1
4. 0.5
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A bag is gently dropped on a conveyor belt moving at a speed of 2 m/s. The coefficient of friction between the conveyor belt and bag is 0.4 Initially, the bag slips on the belt before it stops due to friction. The distance traveled by the bag on the belt during slipping motion is : [Take g = 10 m/s–2 ]
1. 2 m
2. 0.5 m
3. 3.2 m
4. 0.8 m
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A block of mass 10 kg starts sliding on a surface with an initial velocity of 9.8 ms-1. The coefficient of friction between the surface and block is 0.5. The distance covered by the block before coming to rest is: [use g = 9.8 ms-2]
1. 4.9 m
2. 9.8 m
3. 12.5 m
4. 19.6 m
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