Q. No.A meter bridge with two resistance \({R}_{1}\) and \(R_{2}\) as shown in figure was balanced (nul point) at \(40~\text{cm}\) from the point \(P.\) The null point changed to \(50~\text{cm}\) from the point \(P\), when \(16~\Omega\) resistance is connected in parallel to \({R}_{2}\). The value of resistances \({R}_{1}\) and \({R}_{2}\) are:
1. \({R}_2=16~ \Omega, {R}_1=\dfrac{16}{3}~ \Omega\)
2. \({R}_2=4~ \Omega, {R}_1=\dfrac{4}{3} ~\Omega\)
3. \({R}_2=8~ \Omega, {R}_1=\dfrac{16}{3}~ \Omega\)
4. \({R}_2=12 ~\Omega, {R}_1=\dfrac{12}{3}~ \Omega\)
1. \({R}_2=16~ \Omega, {R}_1=\dfrac{16}{3}~ \Omega\)
2. \({R}_2=4~ \Omega, {R}_1=\dfrac{4}{3} ~\Omega\)
3. \({R}_2=8~ \Omega, {R}_1=\dfrac{16}{3}~ \Omega\)
4. \({R}_2=12 ~\Omega, {R}_1=\dfrac{12}{3}~ \Omega\)
Subtopic: Meter Bridge |
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Two resistors \(2~ \Omega\) and \(3~ \Omega\) are connected in the gaps of bridge as shown in figure. The null point is obtained with the contact of jockey at some point on wire \(XY.\) When an unknown resistor is connected in parallel with \(3~ \Omega\) resistor, the null point is shifted by \(22.5~\text{cm}\) toward \(Y.\) The resistance of unknown resistor is: (in \(\Omega\))
1. \(3\)
2. \(2\)
3. \(4\)
4. \(1\)
1. \(3\)
2. \(2\)
3. \(4\)
4. \(1\)
Subtopic: Meter Bridge |
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In a meter bridge experiment to determine the value of unknown resistance, first the resistances \(2~ \Omega\) and \(3~\Omega\) are connected in the left and right gaps of the bridge and the null points is obtained at a distance \(l~\text{cm}\) from the left. Now when an unknown resistance \(x~\Omega\) is connected in parallel to \(3~\Omega\) resistance, the null point is shifted by \(10~\text{cm}\) to the right of wire. The value of unknown resistance \(x\) is: (in \(\Omega\))
1. \(6\)
2. \(7\)
3. \(9\)
4. \(10\)
1. \(6\)
2. \(7\)
3. \(9\)
4. \(10\)
Subtopic: Meter Bridge |
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In the given figure, the balanced length is \(40~\text{cm}\) from the point \({A}.\)
If \(2~\Omega\) is connected parallel to \({R},\) then the change in balance length from \({A}\) will be:
1. \(20~\text{cm}\)
2. \(22.5~\text{cm}\)
3. \(15~\text{cm}\)
4. \(10~\text{cm}\)
If \(2~\Omega\) is connected parallel to \({R},\) then the change in balance length from \({A}\) will be:
1. \(20~\text{cm}\)
2. \(22.5~\text{cm}\)
3. \(15~\text{cm}\)
4. \(10~\text{cm}\)
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In the given meter bridge circuit, a null point is found at \(60 ~\text{cm}\) from the end \(A.\) The unknown resistance \(S\) (in \(\Omega\)) is:
1. \(60~\Omega\)
2. \(80~\Omega\)
3. \(70~\Omega\)
4. \(90~\Omega\)
1. \(60~\Omega\)
2. \(80~\Omega\)
3. \(70~\Omega\)
4. \(90~\Omega\)
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When two resistance \({R}_1\) and \({R}_2\) connected in series and introduced into the left gap of a meter bridge and a resistance of \(10~\Omega\) is introduced into the right gap, a null point is found at \(60~\text{cm}\) from the left side. When \({R}_1\) and \({R}_2\) are connected in parallel and introduced into the left gap, a resistance of \(3~\Omega\) is introduced into the right gap to get the null point at \(40~\text{cm}\) from the left end. The product of the resitance \({R}_1\) and \({R}_2\) is:
1. \(10~\Omega^2\)
2. \(20~\Omega^2\)
3. \(30~\Omega^2\)
4. \(40~\Omega^2\)
1. \(10~\Omega^2\)
2. \(20~\Omega^2\)
3. \(30~\Omega^2\)
4. \(40~\Omega^2\)
Subtopic: Meter Bridge |
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Consider the meter bridge setup shown.
If a shunt resistance is added to \(3~\Omega\) resistor, the balance point shifts by \(22.5~\text{cm}.\) The shunt resistance is equal to:
1. \(1~\Omega\)
2. \(2~\Omega\)
3. \(3~\Omega\)
4. \(4~\Omega\)
If a shunt resistance is added to \(3~\Omega\) resistor, the balance point shifts by \(22.5~\text{cm}.\) The shunt resistance is equal to:
1. \(1~\Omega\)
2. \(2~\Omega\)
3. \(3~\Omega\)
4. \(4~\Omega\)
Subtopic: Meter Bridge |
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R):
In the light of the above statements choose the correct answer from the options given below:
| Assertion (A): | For making a voltmeter, we prefer a voltmeter of resistance of 4000 Ω over a voltmeter of resistance 1000 Ω. |
| Reason (R): | Voltmeter should be of higher resistance such that it draws less current from the circuit. |
In the light of the above statements choose the correct answer from the options given below:
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Subtopic: Meter Bridge |
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A meter bridge setup is shown in the figure. It is used to determine an unknown resistance \(R\) using a given resistor of \(15~\Omega.\) The galvanometer \((G)\) shows a null deflection when the tapping key is at \(43~\text{cm}\) mark from end \(A\). If the end correction for end \(A\) is \(2~\text{cm}\), then the determined value of \(R\) will be:
1. \(19~\Omega\)
2. \( 22~\Omega\)
3. \(25~\Omega\)
4. \( 28~\Omega\)
1. \(19~\Omega\)
2. \( 22~\Omega\)
3. \(25~\Omega\)
4. \( 28~\Omega\)
Subtopic: Meter Bridge |
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In the given figure of the meter bridge experiment, the balancing length \(AC\) corresponding to the null deflection of the galvanometer is \(40\) cm. The balancing length, if the radius of the wire \(AB\) is doubled, will be:
1. \(20\) cm
2. \(30\) cm
3. \(40\) cm
4. \(60\) cm
1. \(20\) cm
2. \(30\) cm
3. \(40\) cm
4. \(60\) cm
Subtopic: Meter Bridge |
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