In BrF3 molecule, the lone pairs occupy equatorial positions to minimize:
| 1. | Lone pair-bond pair repulsion. |
| 2. | Bond pair-bond pair repulsion. |
| 3. | Lone pair-lone pair repulsion and lone pair-bond pair repulsion. |
| 4. | Lone pair-lone pair repulsion. |
The bond angles of \(\mathrm{NH}_3, \mathrm{NH}^+_4~\mathrm{and}~\mathrm{NH}^-_2\) are in the order :
| 1. | \(\mathrm{NH}^-_2> \mathrm{NH}_3>~\mathrm{NH}^+_4\) | 2. | \(\mathrm{NH}^+_4> \mathrm{NH}_3>~\mathrm{NH}^-_2\) |
| 3. | \(\mathrm{NH}_3> \mathrm{NH}^-_2>~\mathrm{NH}^+_4\) | 4. | \(\mathrm{NH}_3> \mathrm{NH}^+_4>~\mathrm{NH}^-_2\) |
Which molecule is least likely to form hydrogen bonds?
| 1. | \(\mathrm{NH}_3\) | 2. | \(\mathrm{NH_2OH}\) |
| 3. | \(\mathrm{HF}\) | 4. | \(\mathrm{CH_3F}\) |
Combination of atoms A and B that forms an anti-bonding molecular orbital is :
1.
2.
3.
4.
Molecule/Ion that is diamagnetic in nature is:
| 1. | \(\mathrm{H}^-_2\) | 2. | \(\mathrm{H}_2\) |
| 3. | \(\mathrm{H}^+_2\) | 4. | \(\mathrm{He}^+_2\) |
A molecule or ion that has an unequal bond length is:
| 1. | \(\mathrm{SF}_4\) | 2. | \(\mathrm{SiF}_4\) |
| 3. | \(\mathrm{XeF}_4\) | 4. | \(\mathrm{BF}^-_4\) |
The specie with the shortest bond length is:
| 1. | \(O^+_2\) | 2. | \(O^-_2\) |
| 3. | \(O^{2-}_2\) | 4. | \(O^{2+}_2\) |
From the following pairs, the two species that are not isostructural are :
| 1. | \(\mathrm{PF}_5~\mathrm{and}~\mathrm{BrF}_5\) | 2. | \(\mathrm{PCl}^+_4~\mathrm{and}~\mathrm{SiCl}_4\) |
| 3. | \(\mathrm{CO}_{3}^{2-} \ \mathrm{and} \ \mathrm{NO}_{3}^-\) | 4. | \(\mathrm{AIF}^{3-}_6~\mathrm{and}~\mathrm{SF}_6\) |
Among the given species, the isostructural pair is:
1. \( \mathrm{NF}_3 \text { and } \mathrm{BF}_3 \)
2. \(\mathrm{BF}_4^{-} \text {and } \mathrm{NH}_4^{+} \)
3. \(\mathrm{BCl}_3 \text { and } \mathrm{BrCl}_3 \)
4. \(\mathrm{NH}_3 \text { and } \mathrm{NO}_3^{-}\)
The hybridization of nitrogen in and respectively is :
1. sp, sp3, and sp2
2. sp, sp2, and sp3
3. sp2, sp, and sp3
4. sp2, sp3, and sp
What is the correct order of the boiling points of \(\mathrm{H}_2 \mathrm{O}, \mathrm{HF}, \text{ and} \ \mathrm{NH}_3\) ?
1. HF > H2O > NH3
2. H2O > HF > NH3
3. NH3 > HF > H2O
4. NH3 > H2O > HF
Which species lacks tetrahedral geometry?
| 1. | 2. | ||
| 3. | 4. |
The species that does not have unpaired electrons is:
| 1. | \(N^+_2\) | 2. | \(O_2\) |
| 3. | \(O^{2-}_2\) | 4. | \(B_2\) |
In which of the following compounds, the hydrogen bonding is strongest?
1. HCl
2. H2O
3. HI
4. H2S
The correct bond angle for \(\mathrm{sp}^2\) hybridization is:
1. \(90^\circ\)
2. \(120^\circ\)
3. \(180^\circ\)
4. \(109^\circ\)
The electronic configurations of the elements A, B, and C are given below.
The stable form of C may be represented by the formula :
| 1. | C | 2. | C2 |
| 3. | C3 | 4. | C4 |
Among the following, the correct order of energies of molecular orbitals of N2 is:
1.
2.
3.
4.
From the perspective of molecular orbital theory, which statement is false?
| 1. | is not a stable molecule. |
| 2. | is not stable but is expected to exist. |
| 3. | Bond strength of is maximum amongst the homonuclear diatomic molecules belonging to the second period. |
| 4. | The order of energies of molecular orbitals in molecule is:
|
What is the correct sequence of bond order for the specified species?
| 1. | \(\mathrm{O}^-_2>\mathrm{O}_2>\mathrm{O}^+_2\) | 2. | \(\mathrm{O}^-_2<\mathrm{O}_2<\mathrm{O}^+_2\) |
| 3. | \(\mathrm{O}^-_2>\mathrm{O}_2<\mathrm{O}^+_2\) | 4. | \(\mathrm{O}^-_2<\mathrm{O}_2>\mathrm{O}^+_2\) |