A cube of side l is placed in a uniform field E, where E=Ei^. The net electric flux through the cube is

(1) Zero

(2) l2E

(3) 4l2E

(4) 6l2E

Subtopic:  Gauss's Law |
 75%
Level 2: 60%+
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Eight dipoles of charges of magnitude \((e)\) are placed inside a cube. The total electric flux coming out of the cube will be: 
1. \(\frac{8e}{\epsilon _{0}}\)
2. \(\frac{16e}{\epsilon _{0}}\)
3. \(\frac{e}{\epsilon _{0}}\)
4. zero

Subtopic:  Electric Dipole |
 76%
Level 2: 60%+
PMT - 1998
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A charge \(q\) is placed at the centre of the open end of the cylindrical vessel. The flux of the electric field through the surface of the vessel is:
1. \(0\)
2. \(\dfrac{q}{\varepsilon_0}\)
3. \(\dfrac{q}{2\varepsilon_0}\)
4. \(\dfrac{2q}{\varepsilon_0}\)

Subtopic:  Gauss's Law |
 51%
Level 3: 35%-60%
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Electric charge is uniformly distributed along a long straight wire of radius \(1\) mm. The charge per cm length of the wire is \(Q\) coulomb. Another cylindrical surface of radius \(50\) cm and length \(1\) m symmetrically encloses the wire as shown in the figure. The total electric flux passing through the cylindrical surface is:

                

1. \(\dfrac{Q}{\varepsilon _{0}}\) 2. \(\dfrac{100Q}{\varepsilon _{0}}\)
3. \(\dfrac{10Q}{\pi\varepsilon _{0}}\) 4. \(\dfrac{100Q}{\pi\varepsilon _{0}}\)
Subtopic:  Gauss's Law |
 65%
Level 2: 60%+
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The S.I. unit of electric flux is 

(1) Weber

(2) Newton per coulomb

(3) Volt × metre

(4) Joule per coulomb

Subtopic:  Gauss's Law |
 53%
Level 3: 35%-60%
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Shown below is a distribution of charges. The flux of electric field due to these charges through the surface S is 

(1) 3q/ε0

(2) 2q/ε0

(3) q/ε0 

(4) Zero

Subtopic:  Gauss's Law |
 83%
Level 1: 80%+
AIIMS - 2003
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Consider the charge configuration and spherical Gaussian surface as shown in the figure. While calculating the flux of the electric field over the spherical surface, the electric field will be due to: 

(1) q2 only

(2) Only the positive charges

(3) All the charges

(4) +q1 and – q1 only

Subtopic:  Gauss's Law |
 62%
Level 2: 60%+
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An electric dipole is put in north-south direction in a sphere filled with water. Which statement is correct ?

(1) Electric flux is coming towards sphere

(2) Electric flux is coming out of sphere

(3) Electric flux entering into sphere and leaving the sphere are same

(4) Water does not permit electric flux to enter into sphere

Subtopic:  Gauss's Law |
 80%
Level 1: 80%+
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The electric flux for Gaussian surface A that encloses the charged particles in free space is (given q1 = –14 nC, q2 = 78.85 nC, q3 = – 56 nC) 

(1) 103 Nm2 C–1

(2) 103 CN-1 m–2

(3) 6.32 × 103 Nm2 C–1

(4) 6.32 × 103 CN-1 m–2

Subtopic:  Gauss's Law |
 61%
Level 2: 60%+
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The electric intensity due to an infinite cylinder of radius R and having charge q per unit length at a distance r(r > R) from its axis is 

(1) Directly proportional to r2

(2) Directly proportional to r3

(3) Inversely proportional to r

(4) Inversely proportional to r2

Subtopic:  Electric Field |
 66%
Level 2: 60%+
PMT - 1993
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